137=3x^2

Solution for 137=3x^2 equation:

137=3x^2

We move all terms to the left:

137-(3x^2)=0

a = -3; b = 0; c = +137;
Δ = b2-4ac
Δ = 02-4·(-3)·137
Δ = 1644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1644}=\sqrt{4*411}=\sqrt{4}*\sqrt{411}=2\sqrt{411}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{411}}{2*-3}=\frac{0-2\sqrt{411}}{-6}
=-\frac{2\sqrt{411}}{-6}
=-\frac{\sqrt{411}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{411}}{2*-3}=\frac{0+2\sqrt{411}}{-6}
=\frac{2\sqrt{411}}{-6}
=\frac{\sqrt{411}}{-3}
$